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How do I find the missing coefficient in the equation of the line that passes through the given point?

+3=5;(2,−1)

User Walleska
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1 Answer

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Final answer:

To find the missing coefficient A in the equation Ax + 3y = 5 for the line passing through the point (2, -1), substitute the values of the point into the equation and solve for A, yielding A = 4 and the completed equation 4x + 3y = 5.

Step-by-step explanation:

The student is tasked with finding the missing coefficient A in the linear equation Ax + 3y = 5 that passes through the point (2, -1). To solve for A, we can substitute the x- and y-values from the point into the equation and solve for A as follows:
1. Substitute x = 2 and y = -1 into the equation:
A(2) + 3(-1) = 5
2. Solve for A:
2A - 3 = 5
2A = 8
A = 4
3. Write the completed equation with the found coefficient A:
4x + 3y = 5

This is the equation of the line with the correct coefficient that passes through the point (2, -1).

The Question is incomplete. The complete question is

Find the missing coefficient in the equation of the line that passes through the given point. Write the completed equation. Ax + 3y = 5, (2, -1)

User Herberth Amaral
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7.4k points