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A gas tank contains 3 gases (N2, O2, and CO2). The total pressure of the gases is 860.0 mmHg. If Pc02 is 150.0 mmHg and Pn2 is 400.0 mmHg, what is the partial pressure of Po2?

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Final answer:

To find the partial pressure of O2 in the gas tank, subtract the partial pressures of CO2 and N2 from the total pressure. The partial pressure of O2 is calculated to be 310.0 mmHg.

Step-by-step explanation:

The question is asking us to calculate the partial pressure of oxygen (O2) in a mixture of gases inside a gas tank where the total pressure and the partial pressures of carbon dioxide (CO2) and nitrogen (N2) are given. According to Dalton's Law of Partial Pressures, the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of the individual gases. Therefore, the partial pressure of O2 can be found by subtracting the partial pressures of CO2 and N2 from the total pressure.

Given that the total pressure (Ptotal) is 860.0 mmHg, the partial pressure of CO2 (PCO2) is 150.0 mmHg, and the partial pressure of N2 (PN2) is 400.0 mmHg, the partial pressure of O2 (PO2) can be calculated as follows:

PO2 = Ptotal - PCO2 - PN2

PO2 = 860.0 mmHg - 150.0 mmHg - 400.0 mmHg

PO2 = 310.0 mmHg

Therefore, the partial pressure of O2 in the gas tank is 310.0 mmHg.

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