Given:
The sequence is -8, -12, -16.
To find:
The nth and 52th term of the given sequence.
Solution:
We have,
-8, -12, -16
It is an AP because the difference between consecutive terms are equal. Here, first term is -8 and the common difference is
![r=a_2-a_1](https://img.qammunity.org/2022/formulas/mathematics/high-school/qhujb9zgs9gcqmljtadqd8e6az8nqz82c6.png)
![r=-12-(-8)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ovmt35j7wvqm7f2oj3se239e6fi3dw6ii9.png)
![r=-12+8](https://img.qammunity.org/2022/formulas/mathematics/high-school/p5g9916fdx8rsqtvw6j9yaxdcrovavcmtw.png)
![r=-4](https://img.qammunity.org/2022/formulas/mathematics/college/v53l0ira43aat1jqpxbidw86u0bszaaf1u.png)
The nth term of an AP is
![a_n=a+(n-1)d](https://img.qammunity.org/2022/formulas/mathematics/high-school/z3ggkqmhdr30c6f6y2dgecyqzzjyb67v0v.png)
Where, a is first term and d is common difference.
Putting a=-8 and d=-4, we get
![a_n=-8+(n-1)(-4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8wcm0ck6hn2i1p3r6g0j4ew22dcgaf8g20.png)
![a_n=-8-4n+4](https://img.qammunity.org/2022/formulas/mathematics/high-school/em388eqgt7tr88zf778p3rdzzfk3e56np8.png)
![a_n=-4-4n](https://img.qammunity.org/2022/formulas/mathematics/high-school/fo0vregszx97tubpohcwsb6yutea7vzwkm.png)
Putting n=52, we get
![a_(52)=-4-4(52)](https://img.qammunity.org/2022/formulas/mathematics/high-school/wm02xy0sjld9qanj7kwcv5m4jkgo5y6cb7.png)
![a_(52)=-4-208](https://img.qammunity.org/2022/formulas/mathematics/high-school/87tkf1y98zmrwax7kas5dejg6k5edrhjx1.png)
![a_(52)=-212](https://img.qammunity.org/2022/formulas/mathematics/high-school/ep9fmwjabpkprryr0eo0kh6x7uzeb4v1io.png)
Therefore, the equation for the nth term of the given sequence is
and the 52nd term of the sequence is -212.