Question

Set hasDigit to true if the 3-character passCode contains a digit.

public class CheckingPasscodes {
public static void main (String[] args) { boolean hasDigit = false;
String passCode = "";
int valid 0;
passCode = "abc";
/* Your solution goes here */
if (hasDigit) { System.out.println("Has a digit.");
}
else { System.out.println("Has no digit.");
}
return;
}

Answer 1

To determine if the passCode contains a digit, iterate over each character and use the Character.isDigit() method. If a digit is found, set hasDigit to true. Then, depending on the value of hasDigit, the program will output whether the passCode contains a digit or not.

Step-by-step explanation:

To set hasDigit to true if the 3-character passCode contains a digit, you need to check each character in the string to see if it is a digit. This can be achieved by using a loop that goes through each character of the string and the Character.isDigit() method to check if the current character is a number. If a digit is found, set hasDigit to true and break out of the loop.

Your solution will look like this:

for (int i = 0; i < passCode.length(); i++) {
if (Character.isDigit(passCode.charAt(i))) {
hasDigit = true;
break;
}
}

After this code segment, the program will print 'Has a digit.' if a digit is found in the passCode, and 'Has no digit.' if there are no digits.

This code snippet will check each character in the passCode string using a for loop. The Character.isDigit() method is a built-in Java method that checks if a character is a digit. If a digit is found, the hasDigit variable is set to true and the loop is exited using the break statement. If after iterating through all the characters, hasDigit is still false, it means there are no digits in the passCode string.