Final answer:
To determine how many grams of ethyl butyrate would be produced from 8.15 g of butanoic acid and excess ethanol, we need to use the stoichiometry of the balanced chemical equation and the given yield percentage.
Step-by-step explanation:
To determine how many grams of ethyl butyrate would be produced from 8.15 g of butanoic acid and excess ethanol, we need to use the stoichiometry of the balanced chemical equation and the given yield percentage. The balanced chemical equation for the reaction is:
CH3CH2COOH + C2H5OH → CH3CH2COOC2H5 + H2O
From the equation, we can see that the coefficient ratio of butanoic acid to ethyl butyrate is 1:1. Therefore, the yield percentage of 78.0% applies to both the butanoic acid and ethyl butyrate.
To calculate the mass of ethyl butyrate produced, we multiply 8.15 g by the yield percentage of 78.0%:
Mass of ethyl butyrate = 8.15 g × 0.780 = 6.357 g