Question

the perimeter of a playing field for a certain sport is 262 ft. the field is a rectangle and the length is 41 ft longer than the width. find the dimensions​

Answer 1

Answer: The width of the playing field = 45 ft

length of playing fiels = 86ft

Explanation:

Step 1

Perimeter of rectangular field is given as 2 ( L+ b)

Let the width be represented as x

such that the length = 41 ft longer than the width be x+ 41

To find the length and breadth

Step 2

Perimeter = 2( L+ b)= 2l + 2b

Perimeter = 2 (x+41 ) + 2 x = 262

2x + 82 + 2x= 262

4x+ 82= 262

4x= 262 - 82

4x= 180

x= 180/4

x= 45

width= 45 ft

length = x+ 41= 45+ 41= 86ft