Final answer:
We have formulated the null and alternative hypotheses for testing whether there's a difference in the mean price for used cars at the Kansas City dealership from the national mean. The p-value can't be provided without conducting the actual hypothesis test. At a significance level of 0.05, the null hypothesis is rejected if the p-value is less than 0.05, otherwise it is not rejected.
Step-by-step explanation:
To determine whether the mean price for used cars at the Kansas City dealership differs from the national mean of $10,192, we can formulate the following hypotheses:
- The null hypothesis (H0): μ = $10,192, which indicates that there is no difference between the national mean and the dealership's mean price.
- The alternative hypothesis (H1): μ ≠ $10,192, signifying that there is a difference between the national mean and the dealership's mean price.
The p-value is a probability that measures the evidence against the null hypothesis. Without specific test statistics, such as the t-score, and without conducting the actual hypothesis test using the sample data, it is impossible to provide the p-value.
For concluding the hypothesis test at a significance level (α) of 0.05, you would compare the p-value to α. If the p-value is less than α, you reject the null hypothesis since there is sufficient evidence to support a significant difference between the dealership's mean price and the national mean. If the p-value is greater than α, you would fail to reject the null hypothesis since there is insufficient evidence to conclude a significant difference.