Question

two parallel plates 10 cm on a side are given equal and opposite charges of magnitude 5.0×10−9c. the plates are 1.5 mm apart. what is the electric field at the center of the region between the plates?

Answer 1

The electric field at the center of the region between two charged parallel plates can be calculated by the formula E = σ / ε0, where σ is the surface charge density and ε0 is the vacuum permittivity constant.

Step-by-step explanation:

The question revolves around the calculation of the electric field between two parallel plates that are charged and separated by a certain distance. To determine the electric field at the center of the region between the plates, we use the formula for a uniform electric field created by parallel plates:

E = σ / ε0

Where E represents the electric field strength, σ is the surface charge density (charge per unit area), and ε0 is the vacuum permittivity constant (8.854 x 10-12 C2/N·m2). In this case, the area A for one plate is (10 cm)2 = 0.01 m2, and the given charge Q is 5.0 x 10-9 C. Therefore, the surface charge density σ = Q/A. Substituting the values, the electric field E at the center of the region between the plates can be calculated.