Question

An object moving in the x direction travels at 3 different constant velocities for 3 time intervals. It starts at 3.3 m/s for 1.5 s, it changes its velocity to some unknown value for 5.0 s, then it goes 2.7 m/s for 1.5 s. If the object's average speed is 3.3 m/s, find the distance traveled during the second time interval.

Answer 1

The distance traveled during the second time interval is 16.5 meters.

Step-by-step explanation:

To find the distance traveled during the second time interval, we need to calculate the displacement during this interval. Displacement is equal to the average velocity multiplied by the time interval. The average velocity can be calculated by dividing the total displacement by the total time taken.

Given that the object's average speed is 3.3 m/s, we can assume that the average velocity is also 3.3 m/s. Therefore, the displacement during the second time interval can be calculated as:

Displacement = Average Velocity * Time Interval = 3.3 m/s * 5.0 s = 16.5 m