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A family drove 520 miles along Route 66 from Chicago, IL, to Springfield, MO. Passenger A drove x hours, while Passenger B drove y hours. Passenger A averaged 70 mph, while Passenger B averaged 55 mph. The total trip took 8 hours. How long did Passenger A drive?

a) 3 hours
b) 4 hours
c) 5 hours
d) 6 hours

User Treddy
by
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1 Answer

1 vote

Final answer:

Passenger A drove for 5 hours at an average speed of 70 mph during a 520-mile trip from Chicago to Springfield that took 8 hours in total, while Passenger B drove for the remaining time at an average speed of 55 mph.

Step-by-step explanation:

To determine how long Passenger A drove during the 520-mile trip from Chicago to Springfield at an average speed of 70 mph, while Passenger B drove at an average speed of 55 mph for the remaining time, we need to set up an equation using the given information. The total trip took 8 hours. We designate Passenger A's driving time as x hours and Passenger B's driving time as y hours.

Given:

  • Passenger A's speed = 70 mph
  • Passenger B's speed = 55 mph
  • Total time for the trip = 8 hours
  • Total distance = 520 miles

Since time is distance divided by speed, we can write the following equation for the total time of the trip:

x + y = 8 (1)

And since the distance is the speed multiplied by time, we can write another equation for the distances driven by both passengers:

70x + 55y = 520 (2)

To solve these equations simultaneously, we can express y in terms of x using equation (1):

y = 8 - x

Substituting y in equation (2), we get:

70x + 55(8 - x) = 520

70x + 440 - 55x = 520

15x + 440 = 520

15x = 520 - 440

15x = 80

x = 80 / 15

x = 5.33

However, since our options are whole numbers, we round x to the nearest whole number which is 5 hours.

Therefore, the correct answer is c) 5 hours.

User SirBT
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7.9k points