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Benjamin is holding a frisbee with a mass of 0.50 kg when Ben decides that he wants it and tries to pull it away from Benjamin. If Benjamin pulls horizontally with a force of 50.0 N and Ben pulls with a horizontal force of 46 N, what is the horizontal acceleration of the frisbee?

a) 4.0 m/s²
b) 0.08 m/s²
c) 0.92 m/s²
d) 50.0 m/s²

User Mithrandir
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1 Answer

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Final answer:

The frisbee experiences a net force of 4 N resulting in a horizontal acceleration of 8.0 m/s² when Benjamin and Ben pull on it with forces of 50.0 N and 46 N, respectively. The correct answer is not listed among the options provided.

Step-by-step explanation:

The problem you've presented is one of Newton's second law of motion, which states that the acceleration of an object is proportional to the net external force acting upon the object and inversely proportional to its mass. In this case, we have a frisbee with a mass of 0.50 kg being pulled on by Benjamin and Ben with forces of 50.0 N and 46 N respectively. Since they are pulling in opposite directions, we need to calculate the net force acting on the frisbee before we can determine the horizontal acceleration.

To calculate the net force, subtract the smaller force from the larger force: 50.0 N - 46 N = 4 N. Now, use Newton's second law (Net Force = Mass × Acceleration) to find the acceleration. Rearrange the equation to solve for acceleration (Acceleration = Net Force / Mass). Substituting the known values gives you an acceleration of 4 N / 0.50 kg = 8.0 m/s². Hence, the correct answer is not listed in the options provided, as they seem to be incorrect.

User Ayumi
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