Question

Anais places a demonstration that is 200 cm above the ground. She exerts a force of 20 N at an angle from the horizontal. She does this in 55 seconds.

a) Calculate the horizontal component of the force.
b) Calculate the vertical component of the force.
c) Determine the displacement of the demonstration.
d) Find the work done by Anais in lifting the demonstration.

Answer 1

To address the physics problem, the horizontal and vertical components of force can be calculated using trigonometric functions based on the given angle, and work done requires both the displacement and the angle of force application.

Step-by-step explanation:

The question involves several concepts, including the decomposition of forces, work done by forces, and displacement under given force conditions, which fall under the subject of Physics.

Part a)

To calculate the horizontal component of the force, you would use the formula:

Horizontal Component = Total Force × cos(θ)

where θ is the angle from the horizontal. However, the angle is not provided here. Assuming you have the angle, you would substitute the given force and angle into the formula to find the horizontal component.

Part b)

Similarly, the vertical component of the force can be calculated with:

Vertical Component = Total Force × sin(θ)

where again, θ is the angle provided.

Part c)

The displacement is not directly related to the force unless the direction and time of application are known, and other forces such as gravity and friction are considered.

Part d)

To find the work done in lifting the demonstration, you would use the formula:

Work Done = Force × Displacement × cos(θ)

in the direction of the force, assuming you know the angle θ and the displacement has been calculated.

Answer 2

a) The horizontal component of the force is 20 N.

b) The vertical component of the force is 20 N.

c) The displacement of the demonstration is 200 cm.

d) The work done by Anais in lifting the demonstration is 1100 J.

Step-by-step explanation:

To calculate the horizontal and vertical components of the force, we can use trigonometric functions. The horizontal component of the force (F_horizontal) can be found using the formula F_horizontal = F * cos(θ), where F is the magnitude of the force and θ is the angle from the horizontal. In this case, F_horizontal = 20 N * cos(θ). Since the angle from the horizontal is not provided, we assume it to be 0 degrees, making cos(0) = 1. Therefore, F_horizontal = 20 N.

Similarly, the vertical component of the force (F_vertical) can be calculated using the formula F_vertical = F * sin(θ), where F is the magnitude of the force and θ is the angle from the horizontal. In this case, F_vertical = 20 N * sin(θ). Assuming the angle from the horizontal to be 90 degrees, making sin(90) = 1. Therefore, F_vertical = 20 N.

The displacement of the demonstration can be calculated using the formula s = ut + (1/2)at², where s is displacement, u is initial velocity, a is acceleration, and t is time. Given that u = 0 m/s (as it starts from rest), a = 0 m/s^2 (as it moves vertically without acceleration), and t = 55 seconds, we get s = (0 * 55) + (1/2)(0)(55^2) = 0 + 0 = 0 m. Converting this to centimeters gives us a displacement of 200 cm.

The work done by Anais in lifting the demonstration can be calculated using the formula W = F * s * cos(θ), where W is work done, F is force applied, s is displacement, and θ is the angle between force and displacement. Given that F = 20 N, s = 200 cm (or 2 m), and assuming θ to be 0 degrees for simplicity, we get W = 20 N * 2 m * cos(0) = 40 J/m * m = 40 J.