Question

suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel after 1.5 * 10^3 seconds

Answer 1

The object travels 144,000,000 feet.

Explanation:

The distance the object travel after t seconds is given by:

`d(t) = 64t^2`

How far would the object travel after 1.5 * 10^3 seconds

This is d when
`t = 1.5 * 10^3 = 1500`, so
`d(1500)`

`d(1500) = 64*1500^2 = 144000000`

The object travels 144,000,000 feet.