Suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel after 1.5 * 10^3 seconds

Question

asked Oct 10, 2022 105k views

1 Answer

Almalerik · Answer 1 · 2022-10-17T08:22:10+0000

Answer:

The object travels 144,000,000 feet.

Explanation:

The distance the object travel after t seconds is given by:

d(t) = 64t^2

How far would the object travel after 1.5 * 10^3 seconds

This is d when
t = 1.5 * 10^3 = 1500 , so
d(1500)

d(1500) = 64*1500^2 = 144000000

The object travels 144,000,000 feet.