Final Answer:
The mass of magnesium fluoride added to the flask is approximately 0.159 grams.
Step-by-step explanation:
To calculate the mass of magnesium fluoride, we can use the formula:
\[ \text{Mass} = \text{Volume} \times \text{Concentration} \times \text{Molar Mass} \]
Given that the volume is \(160.0 \, \text{mL}\), the concentration is \(9.7 \times
\), and the molar mass of magnesium fluoride (MgF₂) is approximately \(62.32 \, \text{g/mol}\), we can substitute these values into the formula:
\[ \text{Mass} = 160.0 \, \text{mL} \times 9.7 \times
\times 62.32 \, \text{g/mol} \]
Calculating this expression yields the mass in grams. To convert this to milligrams, we can multiply by \(1000\) since there are \(1000\) milligrams in a gram:
\[ \text{Mass (mg)} = \text{Mass (g)} \times 1000 \]
The final answer is rounded to two significant digits, providing a mass of approximately \(0.159 \, \text{g}\) or \(159 \, \text{mg}\). This represents the amount of magnesium fluoride added to the reaction flask. The rounded result ensures adherence to significant digit conventions in the final answer.