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A car accelerates from 13m/s to 25m/s in 6.0s. What was its acceration? How far did it travel in this time? Assume constant acceleration.

User AMember
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Final answer:

The acceleration of the car is 2 m/s², and the distance traveled during this time is 114 meters.

Step-by-step explanation:

To calculate the car's acceleration, we can use the formula:

a = Δv / t

where Δv is the change in velocity, and t is the time. The change in velocity (Δv) is the final velocity (v_f) minus the initial velocity (v_i), which is 25 m/s - 13 m/s = 12 m/s. The time (t) given is 6.0 seconds.

Plugging the values in:

a = 12 m/s / 6.0 s = 2 m/s²

So, the acceration of the car is 2 m/s².

To calculate the distance traveled, we can use the formula derived from the equations of motion:

d = v_i • t + (1/2) • a • t²

Inserting the known values (v_i = 13 m/s, a = 2 m/s², t = 6.0 s):

d = (13 m/s • 6.0 s) + (1/2 • 2 m/s² • (6.0 s)²) = 78 m + 36 m = 114 m

The car traveled a distance of 114 meters.

User Michael Moeller
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