Final answer:
The molality of ethanol in the solution is calculated to be 1.51 m by dividing the number of moles of ethanol by the mass of the water solvent in kilograms.
Step-by-step explanation:
The molality of an ethanol solution is calculated by finding the number of moles of ethanol, C2H5OH, divided by the mass of the solvent in kilograms. To find the moles of ethanol, divide the mass of ethanol by its molar mass which is 46.07 g/mol. Therefore, the number of moles of ethanol in 1.34 g is 1.34 g / 46.07 g/mol = 0.0291 mol. Since the mass of water is 19.3 g, we need to convert this to kilograms, which is 0.0193 kg. The molality (m) is then moles of solute per kilogram of solvent, thus 0.0291 mol / 0.0193 kg = 1.51 m.