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The current theory of the structure of the Earth, called plate tectonics, tells us that the continents are in constant motion. Assume that the North American continent can be represented by a slab of rock 5450 km on a side and 36 km deep, and that the rock has an average mass density of 2790 kg/m^3. The continent is moving at the rate of about 3.2 cm/year.

Part 1) What is the mass of the continent? Answer in units of kg.
Part 2) What is the kinetic energy of the continent? Answer in units of J.
Part 3) A jogger (of a mass 79 kg) has the same kinetic energy as that of the continent. What would his speed be? Answer in units of m/s.

User Hwatkins
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Final answer:

The mass of the North American continent is calculated as 2.97182 x 10^19 kg based on its volume and density. Its kinetic energy is approximately 1.536 x 10^11 J, given its velocity. A jogger weighing 79kg would need to travel at a speed of roughly 1.75 x 10^6 m/s to have the same kinetic energy.

Step-by-step explanation:

To find the mass of the continent (North American continent), we can use the formula for mass:

Mass = Volume × Density

The volume of the continent is the product of its length, width, and depth: 5450 km × 5450 km × 36 km = 5450 × 5450 × 36 × 10¹¹ m³ (since 1 km = 10³ m).
Therefore, Volume = 1.06524 × 10¹µ m³.

Given the average mass density of the rock is 2790 kg/m³, we then calculate the mass:

Mass = 1.06524 × 10¹µ m³ × 2790 kg/m³ = 2.97182 × 10¹¹ kg.

Next, to find the kinetic energy of the continent, we use the kinetic energy formula:

KE = ½ × mass × velocity²

The continent's velocity is given as 3.2 cm/year, which needs to be converted to meters per second (m/s):

3.2 cm/year = 3.2 × 10⁻² m/year ≈ 1.01587 × 10⁻⁹ m/s (using 1 year = 3.1536 × 10⁷ seconds).

Therefore, KE = ½ × 2.97182 × 10¹¹ kg × (1.01587 × 10⁻⁹ m/s)² ≈ 1.536 × 10¹± J.

For part 3, if the jogger has a mass of 79 kg and the same kinetic energy as the continent, we solve for the speed by rearranging the kinetic energy formula:

½ × m × v² = KE

v = √(2 × KE / m)

v = √(2 × 1.536 × 10¹± J / 79 kg) ≈ 1.75 × 10¶ m/s.

This value represents the speed of the jogger to have the same kinetic energy as the continent.

User Yrysbek Tilekbekov
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