Question

I need help with this question please and thank you

Answer 1

Given:

Mean = 1600

Standard deviation = 125

Given data follows standard distribution,

`X\text{ \textasciitilde{}N(1600,125)}`

The probability of buyers who paid between $1600 and $1975.

[tex]\begin{gathered} P(1600Now, using the normal table,[tex]P(0So, the percentage of buyers who paid between $1600 and $1975 is 49.87 %