Final answer:
The percent yield of oxygen gas in this chemical reaction is approximately 73.40% (Option B).
Step-by-step explanation:
In order to calculate the percent yield of oxygen gas in the chemical reaction 2KClO3 → 2KCl + 3O2, we need to compare the actual yield of oxygen gas to the theoretical yield. The theoretical yield is the maximum amount of oxygen gas that could be produced based on stoichiometric calculations.
To find the theoretical yield of oxygen gas, we need to calculate the number of moles of KClO3 and use the stoichiometry of the balanced equation to determine the number of moles of O2 produced. From there, we can convert moles of O2 to grams using the molar mass of O2.
The actual yield of oxygen gas is given as 14.9 g. To find the percent yield, we divide the actual yield by the theoretical yield and multiply by 100. The percent yield of oxygen gas in this reaction is approximately 73.40% (Option B).