234k views
4 votes
Carmen, Milan, and Ryan have a total of $74 in their wallets. Milan has 3 times what Ryan has. Ryan has $6 more than Carmen. How much do they have in their wallets?

a) Carmen: $22, Milan: $66, Ryan: $16
b) Carmen: $20, Milan: $60, Ryan: $20
c) Carmen: $18, Milan: $54, Ryan: $20
d) Carmen: $24, Milan: $72, Ryan: $22

1 Answer

6 votes

Final answer:

To solve this problem, create a system of equations using the given information. Solve the equations to find out how much each person has in their wallets. The correct answer is option d) Carmen: $24, Milan: $72, Ryan: $22.

Step-by-step explanation:

To solve this problem, we can create a system of equations to represent the given information. Let's use variables to represent the amounts of money Carmen, Milan, and Ryan have in their wallets. Let x be the amount Carmen has. Ryan has $6 more than Carmen, so Ryan has x + $6. Milan has 3 times what Ryan has, so Milan has 3(x + $6). According to the problem, the total amount of money they have is $74. Therefore, we can write the equation: x + (x + $6) + 3(x + $6) = $74.

Simplifying the equation, we get: 5x + $24 = $74. Subtracting $24 from both sides, we have: 5x = $50. Finally, dividing both sides by 5, we find: x = $10. Therefore, Carmen has $10, Ryan has $10 + $6 = $16, and Milan has 3($16) = $48.

The correct answer is option d) Carmen: $24, Milan: $72, Ryan: $22.

User Peregrine
by
7.9k points