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Sherman made 10 out of his last 16 free throw shots. What percentage of shots did Sherman miss?

a) 20%
b) 37.5%
c) 40%
d) 62.5%

1 Answer

3 votes

Final answer:

Sherman missed 6 out of 16 free throw shots, which is 37.5% of his shots. This is calculated by dividing the missed shots by the total shots and multiplying by 100. Option b) 37.5% is the correct answer.

Step-by-step explanation:

Sherman made 10 out of 16 free throw shots. To find the percentage of shots Sherman missed, we first need to calculate the number of shots he missed. He missed 16 - 10 = 6 shots. Now, to find the percentage of shots missed, we divide the number of missed shots by the total shots taken and multiply by 100:
Missed shot percentage = (missed shots ÷ total shots) × 100
Missed shot percentage = (6 ÷ 16) × 100
Missed shot percentage = 0.375 × 100
Missed shot percentage = 37.5%

Therefore, Sherman missed 37.5% of his shots, which makes option b) 37.5% the correct answer.

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