Final answer:
To find the maximum number of snacks Ms. Young can buy, subtract the cost of the flea collar from her total budget and divide by the cost of a snack. Ms. Young can buy a maximum of 5 snacks.
Step-by-step explanation:
The question comes from the subject of Mathematics as it involves solving an equation for a maximum value within a budget constraint. Ms. Young has <$strong>82.50 to spend at Petco, and she can buy snacks costing <$strong>5.50 each and one flea collar for <$strong>55. The task is to find the maximum number of snacks (s) that Ms. Young could buy, considering the cost of the flea collar.
Using the equation from 4a, which is not provided in the question, we would typically set up an inequality, such as 5.50s + 55 ≤ 82.50, and solve for s. Without the exact equation from 4a, we will proceed with this likely scenario.
Subtract 55 from each side of the inequality to isolate the term with s:
5.50s ≤ 82.50 - 55
5.50s ≤ 27.50
Now, divide both sides of the equation by 5.50 to solve for s:
s ≤ 27.50 / 5.50
s ≤ 5
Because you cannot buy a fraction of a snack, Ms. Young can buy a maximum of 5 snacks and a flea collar with her $82.50 budget.