Final answer:
To calculate the ionic strength of a solution, find the sum of the products of the concentration of each ion and the square of its charge. For this solution, the ionic strength is 0.033 M.
Step-by-step explanation:
To calculate the ionic strength of a solution, we need to find the sum of the products of the concentration of each ion and the square of its charge.
In this case, the solution contains copper (II) nitrate, potassium chloride, and sodium chloride. The copper (II) ion (Cu²+) has a charge of +2, and there is 0.0040 M of copper (II) nitrate, so the contribution to the ionic strength is (0.0040 M) * (+2)² = 0.016 M.
The potassium ion (K⁺) has a charge of +1, and there is 0.010 M of potassium chloride, so the contribution to the ionic strength is (0.010 M) * (+1)² = 0.010 M.
Similarly, the sodium ion (Na⁺) has a charge of +1, and there is 0.0070 M of sodium chloride, so the contribution to the ionic strength is (0.0070 M) * (+1)² = 0.0070 M.
The total ionic strength of the solution is 0.016 M + 0.010 M + 0.0070 M = 0.033 M.