Question

Complete and balance the molecular equation for the reaction of aqueous ammonium bromide, NH₄Br , and aqueous lead(II) acetate, Pb(C₂H₃O₂)₂ . Include physical states. molecular equation: Enter the balanced net ionic equation for this reaction. Include physical states. net ionic equation:

Answer 1

The balanced molecular equation for the reaction between NH4Br and Pb(C2H3O2)2 is NH4Br(aq) + Pb(C2H3O2)2(aq) → PbBr2(s) + 2 NH4C2H3O2(aq), and the net ionic equation is Pb2+(aq) + 2 Br−(aq) → PbBr2(s).

Step-by-step explanation:

The reaction in question involves aqueous ammonium bromide (NH4Br) and aqueous lead(II) acetate (Pb(C2H3O2)2). To complete and balance the molecular equation, we need to predict the products and balance the resulting chemical equation. Lead(II) bromide (PbBr2) is known to be insoluble in water and is likely to form as a precipitate, while ammonium acetate (NH4C2H3O2) is soluble and will remain in the aqueous phase.

The balanced molecular equation for this reaction is:

NH4Br(aq) + Pb(C2H3O2)2(aq) → PbBr2(s) + 2 NH4C2H3O2(aq)

For the net ionic equation, we only include the ions that contribute to the formation of the precipitate, omitting the spectator ions. In this case, the ammonium (NH4+) and acetate (C2H3O2−) ions are spectators. The net ionic equation for the formation of lead(II) bromide precipitate is:

Pb2+(aq) + 2 Br−(aq) → PbBr2(s)