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A 1.0 μF capacitor is being charged by a 6.0 V battery through a 10 MΩ resistor.

Part 1.
Determine the potential across the capacitor at time t=1.0s.
Part 2.
Determine the potential across the capacitor at time t=5.0s.
Part 3.
Determine the potential across the capacitor at time t=20s.

1 Answer

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Final answer:

The potential across a capacitor being charged through a resistor by a battery is calculated using the formula V(t) = V0(1 - e^-t/RC). The time constant (τ) is CR, which in this case is 10 seconds. The voltage on the capacitor can then be calculated at different times using this time constant.

Step-by-step explanation:

To determine the potential across a capacitor at various times when being charged through a resistor by a battery, we use the formula:

V(t) = V0(1 - e-t/RC) (charging),

where V(t) is the potential across the capacitor at time t, V0 is the potential of the battery, R is the resistance, C is the capacitance, and e is the base of the natural logarithm.

The time constant (τ) is given by the product of the resistance (R) and the capacitance (C),

τ = RC,

For our given values, τ = (10 x 106 Ω)(1.0 x 10-6 F) = 10 seconds. Now we can calculate the voltage on the capacitor at different times.

At t = 1.0s, we have

V(1.0) = 6.0V(1 - e-1.0/10)

At t = 5.0s, the equation becomes

V(5.0) = 6.0V(1 - e-5.0/10)

Finally, at t = 20s, the equation is

V(20) = 6.0V(1 - e-20/10)

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