Final answer:
The thermal energy of 100 cm³ of aluminum at 160 °C is 38.88 kJ.
Step-by-step explanation:
The thermal energy of a substance can be calculated using the formula Q = mc∆T, where Q is the thermal energy, m is the mass of the substance, c is the specific heat capacity, and ∆T is the change in temperature.
In this case, we are given the volume of aluminum instead of its mass, but we can calculate the mass using the density of aluminum, which is 2.7 g/cm³. Since the volume is given as 100 cm³, the mass of the aluminum is 2.7 g/cm³ * 100 cm³ = 270 g = 0.27 kg.
Now we can calculate the thermal energy using the specific heat capacity of aluminum, which is 900 J/kg-°C, and the change in temperature, which is 160 °C - 0 °C = 160 °C.
Using the formula, Q = mc∆T, we have Q = 0.27 kg * 900 J/kg-°C * 160 °C = 38,880 J = 38.88 kJ.
Therefore, the thermal energy of 100 cm³ of aluminum at 160 °C is 38.88 kJ.