210k views
1 vote
A refrigerator takes in 20 joules of work and exhausts 40 joules of heat. What is the refrigerator’s coefficient of performance?

1 Answer

4 votes

Final answer:

The coefficient of performance of the refrigerator is calculated as the ratio of the heat removed from the cold reservoir to the work done, which gives a value of 1.0.

Step-by-step explanation:

The student has asked what the coefficient of performance of a refrigerator is when it takes in 20 joules of work and exhausts 40 joules of heat.

The coefficient of performance (COP) for a refrigerator is defined as the ratio of the heat removed from the cold reservoir (Qc) to the work (W) done:

COP = Qc / W

In this case, the heat removed from the cold reservoir (Qc) would be the difference between the heat exhausted to the hot reservoir (Qh) and the work input:

Qc = Qh - W = 40 J - 20 J = 20 J

Therefore:

COP = Qc / W = 20 J / 20 J = 1.0.

The refrigerator's coefficient of performance is 1.0.

User GregC
by
8.0k points