Final answer:
To calculate the molarity of sodium ions in the solution, divide the number of moles of NaCl by the volume of the solution in liters. The molarity of sodium ions in this case is 0.652 M.
Step-by-step explanation:
To calculate the molarity of sodium ions in the solution, we need to first determine the number of moles of sodium ions present in the NaCl. To do this, we can use the molar mass of NaCl and convert the mass of NaCl to moles. The molar mass of NaCl is 58.44 g/mol. Given that 0.950 g of NaCl was dissolved in 25 mL of water, we can convert the mass to moles using the formula:
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
Plugging in the values, we have:
Moles of NaCl = 0.950 g / 58.44 g/mol = 0.0163 mol
Since NaCl dissociates into one sodium ion (Na+) and one chloride ion (Cl-) in water, the number of moles of sodium ions would be the same as the number of moles of NaCl. Therefore, the molarity of sodium ions would be:
Molarity of Sodium Ions = Moles of NaCl / Volume of solution (in L)
Given that the volume of the solution is 25 mL, we should convert it to liters:
Volume of solution (in L) = 25 mL / 1000 mL/L = 0.025 L
Plugging in the values, we have:
Molarity of Sodium Ions = 0.0163 mol / 0.025 L = 0.652 M