Final answer:
Kp can be calculated from Kc for the reaction A(g) + 2B(g) \(\rightarrow\) 3C(g) + D(g) using the formula Kp = Kc(RT)^(\Delta n), where \(\Delta n\) is 1, hence Kp = Kc(RT).
Step-by-step explanation:
The value of Kp in terms of Kc for an equilibrium involving gaseous reactants and products can be determined using the relationship Kp = Kc(RT)^(\Delta n), where R is the ideal gas constant, T is the temperature in Kelvin, and \(\Delta n\) is the change in moles of gas (moles of gaseous products minus moles of gaseous reactants).
For the equilibrium given by A(g) + 2B(g) \(\rightarrow\) 3C(g) + D(g), the \(\Delta n\) would be (3 + 1) - (1 + 2) = 1. Therefore, Kp = Kc(RT). To find Kp if you know Kc, you simply multiply by RT once since \(\Delta n\) is 1. Keep in mind that R is in L·atm/(mol·K) when using atm for pressure.