Final answer:
The smallest positive integer n for which the nth derivative of y = sin x equals y itself is 4, which corresponds to option b.
Step-by-step explanation:
The student is asking for the smallest positive integer n for which the nth derivative of y with respect to x, where y equals sin x, is equal to y itself. To solve this, we take the derivatives of y = sin x:
- y'(x) = cos x
- y''(x) = -sin x
- y'''(x) = -cos x
- y''''(x) = sin x
We find that at n = 4, y(n) equals y. Therefore, the smallest positive integer n for which y(n) = y is 4, which corresponds to option b.