Question

5. The USS Enterprise accelerates from rest at 100,000 m/s^2 for a time of four seconds. How far did the ship travel in that time?

a. 200,000 meters
b. 400,000 meters
c. 800,000 meters
d. 1,600,000 meters

Answer 1

The USS Enterprise will travel a distance of 800,000 meters when it accelerates from rest at 100,000 m/s² for 4 seconds, according to the formula s = ut + ½ at².

Step-by-step explanation:

The USS Enterprise would travel if it accelerated from rest at 100,000 m/s² for a time of four seconds. To find the distance traveled during acceleration, one can use the formula of motion under constant acceleration, which is s = ut + ½ at², where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the initial velocity (u) is 0 m/s (since the spaceship starts from rest), the acceleration (a) is 100,000 m/s², and the time (t) is 4 s. Plugging in these values, we get:

s = (0 m/s)(4 s) + ½ (100,000 m/s²)(4 s)²
s = 0 + ½ (100,000 m/s²)(16 s²)
s = ½ (1,600,000 m)
s = 800,000 m

Therefore, the correct answer is (c) 800,000 meters.