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Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates.

Slope: -3/2
Ordered pair: (-1,2)
a) y = -3/2x - 5/2
b) y = -3/2x + 5/2
c) y = 3/2x - 5/2
d) y = 3/2x + 5/2

1 Answer

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Final answer:

The equation of the line with slope -3/2 that passes through the point (-1,2) in slope-intercept form is y = -3/2x + 5/2.

Step-by-step explanation:

To find the equation of the line in slope-intercept form (y = mx + b), where 'm' is the slope and 'b' is the y-intercept, we use the given slope and the point through which the line passes. In this case, the slope is given as -3/2, and the line passes through the point (-1, 2).

First, we plug the slope (m = -3/2) into the slope-intercept form:


y = (-3/2)x + b

Next, we use the coordinates of the given point (-1, 2) to find the y-intercept (b). We plug x = -1 and y = 2 into the equation:


2 = (-3/2)(-1) + b

Solving for 'b', we get:


2 = 3/2 + b
b = 2 - 3/2
b = 4/2 - 3/2
b = 1/2

Now that we have both the slope and the y-intercept, we can write the final equation:


y = (-3/2)x + 1/2

Matching this with the given options, the correct equation is:


b) y = -3/2x + 5/2