Question

An object is thrown straight up with an initial velocity of 5 m/s.

A) How long does it take to reach its maximum height?
a) t = 0.5 seconds
b) t = 1.0 seconds
c) t = 1.5 seconds
d) t = 2.0 seconds

B) What is its maximum height?
a) h = 5 m
b) h = 10 m
c) h = 12.5 m
d) h = 25 m

Answer 1

The time it takes for the object to reach its maximum height is approximately 0.51 seconds, and the maximum height is approximately 1.26 meters.

Step-by-step explanation:

The time it takes for the object to reach its maximum height can be determined using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. In this case, the object is thrown straight up, so the acceleration is the acceleration due to gravity, which is approximately 9.8 m/s². The initial velocity is 5 m/s, so we can rearrange the equation to find the time:

t = (v - u) / a = (0 - 5) / (-9.8) = 0.51 seconds (approximately).

The maximum height can be determined using the equation h = ut + (1/2)at², where h is the maximum height, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the values, we get:

h = (5 * 0.51) + (1/2) * (-9.8) * (0.51)² ≈ 1.26 meters.

Therefore, the correct answers are:

A) t = 0.5 seconds

B) h = 1.26 meters