Final answer:
The equation of the line in point-slope form that passes through (2, 3) and is perpendicular to y=1/3x+2 is y - 3 = -3(x - 2).
Step-by-step explanation:
To write the equation of the line in point-slope form that passes through point P(2, 3) and is perpendicular to the line y = 1/3 x + 2, we need to use the negative reciprocal of the slope of the given line. The slope of y = 1/3 x + 2 is 1/3, so the slope of the perpendicular line will be -3 (the negative reciprocal of 1/3). The point-slope form of an equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a given point on the line.
Thus, for the point (2, 3) and the slope -3, the equation is:
y - 3 = -3(x - 2).