Final answer:
To find the number of grams of SiH₄ that contain 8.23 x 10²² atoms of hydrogen, we can use the molar mass of SiH₄ and Avogadro's number. The number of grams of SiH₄ is 4.37 g.
Step-by-step explanation:
To determine the number of grams of SiH₄ that contain 8.23 x 10²² atoms of hydrogen, we need to use the molar mass of SiH₄ and Avogadro's number. The molar mass of SiH₄ is 32.07 g/mol. Since SiH₄ contains 4 hydrogen atoms, one mole of SiH₄ contains 4 moles of hydrogen atoms. Avogadro's number is 6.022 x 10²³ molecules/mol, which means there are 6.022 x 10²³ atoms of hydrogen in one mole of SiH₄. To find the number of moles of SiH₄ that contain 8.23 x 10²² atoms of hydrogen, we can set up a proportion:
(8.23 x 10²² atoms H) / (6.022 x 10²³ atoms H/mol) = (x mol SiH₄) / (1 mol SiH₄)
Solving for x, we get x = (8.23 x 10²² atoms H) / (6.022 x 10²³ atoms H/mol) = 0.1363 mol SiH₄
Finally, to find the number of grams of SiH₄, we multiply the number of moles by the molar mass:
0.1363 mol SiH₄ * 32.07 g/mol = 4.37 g
Therefore, 8.23 x 10²² atoms of hydrogen is contained in 4.37 grams of SiH₄.