Final answer:
To calculate the electric flux through a rectangular plane aligned with an electric field, multiply the field magnitude by the plane's area. With a field of 3.64 kN/C and an area of 0.245 m², the flux is 892.4 N·m²/C.
Step-by-step explanation:
To calculate the electric flux through a rectangular plane due to an electric field applied along the x-axis, you can use the formula for electric flux (Φ), which is the product of the electric field magnitude (E) and the area through which the field lines pass (A), assuming the field is perpendicular to the area. The formula is given by Φ = E * A * cos(θ), where θ is the angle between the field and the normal to the surface.
For this problem, since the electric field is aligned along the x-axis and the rectangular plane is also oriented such that its normal is along the x-axis, the angle θ is 0°. The cosine of 0° is 1, so the flux calculation simplifies to Φ = E * A. Given that E = 3.64 kN/C (or 3640 N/C) and the area A can be calculated by multiplying the width (0.350 m) by the length (0.700 m), you get:
A = 0.350 m * 0.700 m = 0.245 m²
Subsequently, the electric flux Φ is:
Φ = 3640 N/C * 0.245 m² = 892.4 N·m²/C.