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a generic salt, ab2 , has a molar mass of 165 g/mol and a solubility of 5.90 g/l at 25 °c. ab2(s)↽−−⇀a2 (aq) 2b−(aq) what is the sp of this salt at 25 °c?

User Kwcto
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Final answer:

The solubility product constant (Ksp) of the salt AB2 at 25 °C is calculated using its molar mass and solubility, leading to the stoichiometric dissolution equation and subsequent Ksp expression.

Step-by-step explanation:

The student asked about the solubility product constant (sp or Ksp) of a salt AB2 at 25 °C, given its molar mass and solubility. To calculate the Ksp for AB2, we can use the provided solubility of 5.90 g/L which can be converted to molarity by dividing by the molar mass, resulting in a solubility of 8.8 × 10-5 M. Since the dissolution reaction is AB2(s) ⇌ A2+(aq) + 2B-(aq), for every 1 mol of AB2 that dissolves, 1 mol of A2+ ions and 2 mol of B- ions are produced in solution, making the Ksp expression:

Ksp = [A2+][B-]2 = (8.8 × 10-5)(2 × 8.8 × 10-5)2 M3

The calculated value will give the Ksp for AB2 at 25 °C.

User Robin Newhouse
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