Using the equations of motion for free fall, it is calculated that both balls dropped from a height of 5.0 meters will hit the ground in 1 second when the acceleration due to gravity is 10 m/s².
To determine how long it takes for two balls to hit the ground when dropped from a height of 5.0m, we can use the equations of motion under constant acceleration. The acceleration due to gravity (g) is provided as 10 m/s2, which simplifies the calculations. The equation for the fall time (t) without initial velocity is given by the following:
t = √(2h/g), where h is the height and g is the acceleration due to gravity.
Substituting the given values, we get t = √(2*5.0 m / 10 m/s2) = √(1 s2) = 1 s. So, both balls take 1 second to reach the ground, assuming there is no air resistance.
The equation of motion for free fall under the influence of gravity allows us to calculate that it takes 1 second for the balls to reach the ground from a height of 5.0 meters when the acceleration due to gravity is considered to be 10 m/s2.