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Jamilla constructed a round igloo with a radius of 2 feet. Padima wanted the base area of his igloo to be 4 times larger than Jamilla's. Which change in dimension did Padima have to make?

a) Padima needed to double the radius.
b) Padima needed to quadruple the radius.
c) Padima needed to double the circumference.
d) Padima needed to double both the radius and the circumference.

User Chanz
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1 Answer

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Final answer:

To make the base area of Padima's igloo 4 times larger than Jamilla's, Padima needed to double the radius from 2 feet to 4 feet. Due to the area formula A = πr², doubling the radius of a circle results in quadrupling the area, which satisfies Padima's requirement.

Step-by-step explanation:

To determine which change in dimension Padima had to make to ensure his igloo's base area was exactly 4 times larger than Jamilla's, we need to recall the formula for the area of a circle, which is A = πr². Given that Jamilla has constructed a round igloo with a radius of 2 feet, the area of her igloo's base would be π(2²) = 4π square feet. If Padima wants his igloo's base to have an area 4 times larger, we would need an area of 4 × (4π) = 16π square feet.

To find the necessary radius for Padima's igloo, we set up the equation: 16π = πr². Dividing both sides by π, we get ²16 = r². Taking the square root of both sides gives us r = 4 feet. Thus, Padima needed to double the radius of her igloo from 2 feet to 4 feet to make the base area 4 times larger.

Option a) is correct because doubling the radius of a circle results in a new area which is four times the original area because the area of a circle is proportional to the square of the radius. Doubling the radius (2r) and squaring it gives (2r)² = 4r², showing that the area is four times larger.

User Onejeet
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