Question

Marcy pulls a backpack on wheels down the 100-m hall. The 60-N force is applied at an angle of 30° above the horizontal. How much work is done by Marcy?

a) 6,000 J
b) 3,000 J
c) 5,196 J
d) 3,464 J

Answer 1

The work done by Marcy can be calculated using the horizontal component of the force and the displacement in the direction of the force. The correct answer is 5,196 J.

Step-by-step explanation:

Work done by a force is calculated as the product of the force and the displacement in the direction of the force. In this case, Marcy applies a 60-N force at an angle of 30° above the horizontal to pull the backpack down the 100-m hall.

The horizontal component of the force can be found using the formula:

Fhorizontal = F * cos(theta)

The vertical component of the force can be found using the formula:

Fvertical = F * sin(theta)

Since the displacement is in the horizontal direction, the vertical component of the force does no work. Therefore, the work done by Marcy can be calculated as:

Work = Fhorizontal * distance

Substituting the given values:

Work = 60 * cos(30°) * 100 = 5,196 J

Therefore, the correct answer is c) 5,196 J.