Question

What is the displacement after 3 seconds of a particle moving along a line if s(t) = t³+ 2t², where s is distance in feet, and t is time in seconds?

A. 15 ft.
B. 24 ft.
C. 31 ft.
D. 33 ft.
E. 45 ft.

Answer 1

The displacement of a particle after 3 seconds, given the distance function s(t) = t³ + 2t², is 45 feet when computed as s(3) = 3³ + 2(3)².

Step-by-step explanation:

To find the displacement of a particle after 3 seconds when the distance function is given by s(t) = t³ + 2t², we substitute the time value t = 3 seconds into the equation.

s(3) = 3³ + 2(3)²
= 27 + 2(9)
= 27 + 18
= 45 feet.

Therefore, the displacement after 3 seconds is 45 feet.