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If 23,000 joules of energy are used to heat water by 4.00 °C, what is the mass of the water?

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The mass of the water can be calculated using the specific heat capacity of water and the energy provided. By rearranging the formula Q = m × c × ΔT and inputting the respective values, we find the mass of the water heated by 23,000 joules for a 4 °C temperature increase.

To determine the mass of the water when 23,000 joules of energy are used to heat it by 4.00 °C, we use the specific heat capacity of water and the formula: Q = m × c × ΔT, where Q stands for the heat energy in joules, m for the mass of the water in grams, c for the specific heat capacity, and ΔT for the temperature change in degrees Celsius.

The specific heat capacity of water is 4.184 J/g°C. Reorganizing the formula to solve for m gives us m = Q / (c × ΔT). Substituting in the values gives us m = 23,000 J / (4.184 J/g°C × 4.00 °C), which calculates to the mass of the water.

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