Question

Give the theoretical yield, in moles, of CO₂ from the reaction of 4.00 moles of C₈H₁₈ with 4.00 moles of O₂.

2 C₈H₁₈ +25O₂→16 CO₂+18H₂O (Enter numeric answer only, do not write any units)____

Answer 1

The theoretical yield of CO₂ from 4.00 moles of C₈H₁₈ with 4.00 moles of O₂, based on the stoichiometry of the balanced chemical equation and the limiting reagent, is 5.12 moles.

Step-by-step explanation:

The theoretical yield of CO₂ from 4.00 moles of C₈H₁₈ reacting with 4.00 moles of O₂ can be determined by using stoichiometry based on the balanced chemical equation:

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

According to the equation, 2 moles of C₈H₁₈ produce 16 moles of CO₂. So 4 moles of C₈H₁₈ would theoretically produce twice that amount, 32 moles of CO₂. However, we are limited by the amount of available O₂. With 4 moles of O₂ available, and considering the need for 25 moles of O₂ to react with 2 moles of C₈H₁₈, oxygen is the limiting reagent. Since we have only 4 moles of O₂ (1/25 of the necessary amount to fully react with 4 moles of C₈H₁₈), we can only produce 1/25 of the CO₂ that would be produced if we had enough oxygen. Therefore, the theoretical yield of CO₂ in this reaction is:

32 moles of CO₂ × (4/25) = 5.12 moles of CO₂

The theoretical yield in moles of CO₂ from the reaction, given the limiting reagent, is 5.12 moles.