Final answer:
The potential needed to store 1.00 J of energy in a 0.700 μF capacitor is approximately 1692 V.
Step-by-step explanation:
To find the potential needed to store a certain amount of energy in a capacitor, you can use the formula:
E = 1/2 * C * V^2
Where E is the energy stored, C is the capacitance, and V is the potential difference. Rearranging the formula, we get:
V = sqrt(2 * E / C)
Plugging in the given values, we have:
V = sqrt(2 * 1.00 J / 0.700 μF)
Converting the capacitance to farads:
V = sqrt(2 * 1.00 J / 0.700 * 10^-6 F)
Calculating:
V ≈ sqrt(2.86 * 10^6)
V ≈ 1692 V