Final answer:
The potential will be 120 V at a distance of 7.5 x 10^-3 meters from the charge.
Step-by-step explanation:
To find the distance from the charge where the potential is 120 V, we need to use the equation for electric potential:
V = k * Q / r
where V is the potential, k is the Coulomb's constant (9 x 10^9 N*m^2/C^2), Q is the charge of the point charge, and r is the distance from the charge.
Since the potential is zero at infinity, we can rearrange the equation to solve for r:
r = k * Q / V
Substituting the given values, we have:
r = (9 x 10^9 N*m^2/C^2) * (1.00 x 10^-6 C) / 120 V
r = 7.5 x 10^-3 m
Therefore, the potential will be 120 V at a distance of 7.5 x 10^-3 meters from the charge.