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Solve the system by elimination -2x 2y 3z=0

User Gamopo
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Final answer:

To solve the system by elimination, multiply the first equation by -2 and the second equation by 2 to make the coefficients of x cancel out. When you solve for y, you find y = 0. Substitute this value back into either equation to solve for x and z.

Step-by-step explanation:

To solve the system by elimination, we can multiply the first equation by -2 and the second equation by 2 to make the coefficients of x cancel out. This gives us:

-4x + 4y - 6z = 0

4x + 4y + 6z = 0

Adding these two equations together eliminates the x terms:

8y = 0

Dividing both sides by 8 gives us:

y = 0

Now we can substitute the value of y back into either of the original equations to solve for x and z.

User Bvr
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