Question

still for the reaction: 3bro-(aq) --> bro3-(aq) 2br-(aq), what is the rate of reaction in m/s, if δ[bro- ]/δt = -0.212 m/s?

Answer 1

The rate of appearance of Br₂(aq) at a particular moment can be calculated using the rate of disappearance of Br(aq) and the stoichiometry of the reaction.

Step-by-step explanation:

In the reaction 5Br¯(aq) + BrO3¯(aq) + 6H+ (aq) → 3Br₂(aq) + 3H₂O(1), the balanced chemical equation shows that 5 moles of Br¯ react to form 3 moles of Br₂. The rate of disappearance of Br(aq) is given as 3.5 × 10-4 mol L-1 s-1. Since the stoichiometry of the reaction is 5:3, we can calculate the rate of appearance of Br₂(aq) as follows:

1. Calculate the molar ratio between Br and Br₂ in the reaction. 3 moles of Br₂ are formed from 5 moles of Br. So, the molar ratio is 3/5 = 0.6.
2. Multiply the rate of disappearance of Br(aq) by the molar ratio calculated in step 1 to get the rate of appearance of Br₂(aq). (3.5 × 10-4 mol L-1 s-1) * 0.6 = 2.1 × 10-4 mol L-1 s-1.

Therefore, the rate of appearance of Br₂(aq) at that moment is 2.1 × 10-4 mol L-1 s-1.