Question

X² - 4x + 1 = 0Can you please solve that for me?

Answer 1

`x=3.732;x=0.268`

Step-by-step explanation

We want to solve the given equation for x:

`x^2-4x+1=0`

To do this, apply the quadratic formula:

`x=(-b\pm√(b^2-4ac))/(2a)`

where a = coefficient of x²

b = coefficient of x

c = constant term

From the equation, we have that:

`a=1,b=-4,c=1`

Therefore, solving for x:

`\begin{gathered} x=(-(-4)\pm√((-4)^2-(4*1*1)))/(2(1)) \\ x=(4\pm√(16-4))/(2)=(4\pm√(12))/(2) \\ x=(4+√(12))/(2);x=(4-√(12))/(2) \\ x=(4+3.464)/(2);x=(4-3.464)/(2) \\ x=(7.464)/(2);x=(0.536)/(2) \\ x=3.732;x=0.268 \end{gathered}`

That is the solution to the equation.