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A shell is fired from the ground with an initial speed of 1700 m/s at an angle of 55 degrees to the horizontal. Neglecting air resistance, what is the amount of time the shell is in motion if its horizontal range is 294897.96 meters?

a) 1700 seconds
b) 1000 seconds
c) 500 seconds
d) 250 seconds

User Maynard
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1 Answer

3 votes

Final answer:

To find the time the shell is in motion, we need to calculate the horizontal velocity and then use it to determine the time of flight. By using trigonometry, we can find that the horizontal velocity is 926.98 m/s. Then, by dividing the horizontal range by the horizontal velocity, we can find that the time of flight is approximately 318.53 seconds.

The correct option is not given.

Step-by-step explanation:

To find the time the shell is in motion, we need to first determine the horizontal velocity of the shell. We can do this by using the initial speed of 1700 m/s and the angle of 55 degrees. Using trigonometry, we can determine that the horizontal velocity is given by:

Vx = initial speed * cos(angle)

Plugging in the values, we have:

Vx = 1700 m/s * cos(55) = 926.98 m/s

Next, we can use the horizontal velocity to calculate the time of flight. The horizontal range is given as 294897.96 meters, which is equal to the horizontal velocity multiplied by the time of flight. Rearranging the formula, we have:

Time of flight = Horizontal range / horizontal velocity

Plugging in the values, we get:

Time of flight = 294897.96 m / 926.98 m/s = 318.53 seconds

Therefore, the amount of time the shell is in motion is approximately 318.53 seconds.

The correct option is not given.

User Carpenter
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