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A 2.5 moles of gas occupies a volume of 5.55 L at 30.5 degrees Celsius. Calculate its pressure.

a) 0.99 atm
b) 1.1 atm
c) 2.2 atm
d) 0.55 atm

User Asaf Katz
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Final answer:

Using the Ideal Gas Law, the pressure of 2.5 moles of gas at 30.5 degrees Celsius and occupying 5.55 L is calculated to be approximately 1.1 atm. The correct answer is b) 1.1 atm.

Step-by-step explanation:

To calculate the pressure of 2.5 moles of gas occupying 5.55 L at 30.5 degrees Celsius, we use the Ideal Gas Law equation:

PV = nRT

Where:

First, convert the temperature from Celsius to Kelvin:
T(K) = 30.5 + 273.15 = 303.65 K.

Then apply the Ideal Gas Law:

P = nRT/V = (2.5 moles * 0.0821 L·atm/(mol·K) * 303.65 K) / 5.55 L

After calculating, we find that P ≈ 1.1 atm. Therefore, the correct answer is b) 1.1 atm.

The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions, although it has several limitations. It was first stated by Benoît Paul Émile Clapeyron in 1834 as a combination of the empirical Boyle's law, Charles's law, Avogadro's law, and Gay-Lussac's law. The ideal gas law is often written in an empirical form

User Stackoverblown
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